Question

The mass of each lead ball in Cavendish’s experiment was 195 kg. Given the value of G, the magnitude of the expected force of attraction between two of these balls if their centres were separated by 1.0400 m is ___x10^-6 N.

Answer 1

$F=GMm/r^2=6.67\cdot10^{-11}\cdot195\cdot195/1.04^2=2.3\cdot10^{-6}\ (N)$ . Answer