Answer to Question #268529 in Physics for Anop

Question

A vial of blood in a horizontal centrifuge has mass of 0.5 kg. The vial has a length

of 10 cm and is 30 cm from the center of the device. If the centrifuge is spinning at 3000 rpm,

how much work is done by the net force during each revolution? (Use g = 10 m/s2 for your

calculation)

A. 0 J

B.  J

C. 2 J

D. 3 J

Answer 1

Given:

$m=0.5\:\rm kg$

$L=0.1\:\rm m$

$d=0.3\:\rm m$

$n=3000\:\rm rpm=50\: rev/s$

The net force is the centripetal force. The work done by centripetal force is zero.

Answer: A. 0J