The density of gold at 20°C is 19,300kg/m3. Find the density at 100°C?
V=V0(1+αΔT)→ρ=ρ0/(1+αΔT)→V=V_0(1+\alpha\Delta T)\to\rho=\rho_0/(1+\alpha\Delta T)\toV=V0(1+αΔT)→ρ=ρ0/(1+αΔT)→
ρ=19300/(1+42⋅10−6⋅(100−20))=19235 (kg/m3)\rho=19300/(1+42\cdot10^{-6}\cdot(100-20))=19235\ (kg/m^3)ρ=19300/(1+42⋅10−6⋅(100−20))=19235 (kg/m3)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments