Answer to Question #268267 in Physics for Lili

Question

In the figure, a 4.4 kg block slides along a track from one level to a higher level after passing through an intermediate valley. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is v₀ = 7.3 m/s, the height difference is h = 1.1 m, and μ_k= 0.632. Find d.

The tolerance is +-1 in the 3rd significant digit

Answer 1

$$0.5mv^2=mgh+\mu mg d\\ 0.5(7.3)^2=9.8(1.1+0.632d)\\d=2.56\ m$$