A roller coaster ride in a park includes a vertical drop of 60 m. Assume that the roller coaster has a speed of nearly zero when it reaches the top of the hill. Neglecting friction, find the speed of the riders at the bottom of the hill
"mgh=mv^2\/2\\to v=\\sqrt{2gh}=\\sqrt{2\\cdot 9.8\\cdot 60}=34.3\\ (m\/s)" . Answer
Comments
Leave a comment