a 3.00 kg object experiences a 16.0 N force pulling south, a 26.3 N force pulling east and a 21.0 N force pulling at 27 degrees S of E. The magnitude of the acceleration experienced by the object is?
Fx=26.3+21⋅cos27°=45.9 (N)F_x=26.3+21\cdot\cos27°=45.9\ (N)Fx=26.3+21⋅cos27°=45.9 (N)
Fy=16+21⋅sin27°=25.5 (N)F_y=16+21\cdot\sin27°=25.5\ (N)Fy=16+21⋅sin27°=25.5 (N)
F=45.92+25.52=52.5 (N)F=\sqrt{45.9^2+25.5^2}=52.5\ (N)F=45.92+25.52=52.5 (N)
a=F/m=52.5/3=17.5 (m/s2)a=F/m=52.5/3=17.5\ (m/s^2)a=F/m=52.5/3=17.5 (m/s2) . Answer
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