Answer to Question #267503 in Physics for babar

Question

The diagram below shows the velocity against time graph for a stone thrown vertically upwards.

a.Explain what the gradient of the graph represents in this case.

b.Where is the ball in its flight when the time t

is 1.5 s?

c. Use the information on the graph to determine the maximum height attaine

d by the stone.

Answer 1

a. The gradient is acceleration.

b. The height is

$$h=vt-gt^2/2=11·9.8-9.8·1.5^2/2=5.5\text{ m}.$$

c. The maximum height is

$$h=v^2/2g=11^2/(2·9.8)=6.2\text{ m}.$$