Answer to Question #267475 in Physics for Tol

Question

 A person has a weight of 882 N at surface of the earth. Find his weight, W, and the acceleration due to gravity, ag, at an altitude of two earth’s radius, r.

Answer 1

$g=GM/(R+h)^2=6.67\cdot10^{-11}\cdot5.97\cdot10^{24}/(6371000+6371000)^2=$

$=2.45\ (m/s^2)$

$W=mg=(882/9.8)\cdot2.45=220.5\ (N)$