Question #267465

A kettle contains 0.6kg water. The heat absorbed by the water is 18Js-1 in 20 minutes. Calculate the rise in temperature of the water [Specific heat capacity of water=4200 Jkg-1Celcius-1]


1
Expert's answer
2021-11-17T10:37:56-0500

The rise of temperature:


Δt=Q/(cm)=qt/(cm),Δt=18⋅20⋅60/(4200⋅0.6)=8.6°C.\Delta t=Q/(cm)=qt/(cm),\\ \Delta t=18·20·60/(4200·0.6)=8.6°\text C.


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