Question

an object initially has a velocity 6m/s, travel a distance of 24m with an acceleration of -4m/s. find the final velocity of the object .

Answer 1

We can find the final velocity of the object from the kinematic equation (it seems there is a mistake in condition of the question, because the square root becomes imaginary, so let's suppose that the object travel a distance of 4 m):

$$v^2=v_0^2+2ad,$$ $$v=\sqrt{v_0^2+2ad},$$ $$v=\sqrt{(6\ \dfrac{m}{s})^2+2\times(-4\ \dfrac{m}{s^2})\times4\ m}=2\ \dfrac{m}{s}.$$