Answer to Question #266325 in Physics for Ian

Question

A projectile is fired horizontally at a speed of 8 m/s from an 80-m-high cliff. Find (a) The velocity just before the projectile hits the ground.

Answer 1

The velocity is

$$v=\sqrt{v_x^2+v_y^2},\\\space\\ v=\sqrt{v_x^2+(\sqrt{2gh})^2}=40\text{ m/s},\\\space\\ \theta=\arctan\frac{\sqrt{2gh}}{v_x}=89.6°$$