Answer to Question #265788 in Physics for MCC

Question

A constant torque of 35 Nm is applied to a wheel whose moment of inertia is 1.5 kg m². Find the Angular Acceleration. Also, find the angular speed at the end of 25 seconds

Answer 1

By the definition of the torque we have:

$$\tau = I\alpha,$$ $$\alpha=\dfrac{\tau}{I}=\dfrac{35\ N\times m}{1.5\ kg\times m^2}=23.3\ \dfrac{rad}{s^2}.$$

We can find the angular speed at the end of 25 seconds as follows:

$$\omega=\omega_0+\alpha t,$$ $$\omega=0+23.3\ \dfrac{rad}{s^2}\times25\ s=582.5\ \dfrac{rad}{s}.$$