Suppose the radius is measured to be r=6.0cm+-0.1cm
a,the true value of the radius lies between _
b,what is the significant figure of area
a. "5.9\\le r\\le6.1\\ cm"
b. "A=\\pi r^2=3.14\\cdot6.0^2=113.0\\ (m^2)"
"\\frac{\\Delta A}{A}=\\frac{2\\Delta r}{r}\\to \\Delta =A\\cdot\\frac{2\\Delta r}{r}=113.0\\cdot\\frac{2\\cdot0.1}{6.0}=3.8\\ (m^2)"
"A=(113.0\\pm3.8)\\ m^2"
Comments
Leave a comment