Question #265132

Problem 1: A soccer ball is kicked horizontally off a 22.0-meter high hill and lands a distance of 35.0 meters from the edge of the hill. Determine the initial horizontal velocity of the soccer ball. 



Problem 2: A long jumper leaves the ground with an initial velocity of 12 m/s at an angle of 28-degrees above the horizontal. Determine the time of flight, the horizontal distance, and the peak height of the long-jumper.


1
Expert's answer
2021-11-14T17:17:48-0500

Problem 1: the initial velocity is


v=R/t=R/2h/g=16.5 m/s.v=R/t=R/\sqrt{2h/g}=16.5\text{ m/s}.

Problem 2: the time of flight, the horizontal distance, and the peak height:


t=2vsinθg=1.15 s, R=v2sin(2θ)g=12.2 m, H=v2sin2θ2g=1.62 m.t=\frac{2v\sin\theta}{g}=1.15\text{ s},\\\space\\ R=\frac{v^2\sin(2\theta)}{g}=12.2\text{ m},\\\space\\ H=\frac{v^2\sin^2\theta}{2g}=1.62\text{ m}.


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