A 5.0 kg bucket of water is raised from a well by a rope. If the upward accelaration of the bucket is 3.0m/s2 find the force exerted by the rope on the bucket
Given:
"m=5.0 \\:\\rm kg"
"a=3.0 \\:\\rm m\/s^2"
The Newton's second law says
"ma=F-mg"Hence
"F=m(a+g)=5.0*(3.0+9.8)=64\\:\\rm N"
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