Question

A 5.0 kg bucket of water is raised from a well by a rope. If the upward accelaration of the bucket is 3.0m/s2 find the force exerted by the rope on the bucket

Answer 1

Given:

$m=5.0 \:\rm kg$

$a=3.0 \:\rm m/s^2$

The Newton's second law says

$$ma=F-mg$$

Hence

$$F=m(a+g)=5.0*(3.0+9.8)=64\:\rm N$$