A concave mirror has a radius of curvature of 40.5 cm and is positioned at a distance such that the upright image of a person's face is 1.5 times the size of his face. How far is the mirror from the person's face?
m=−vu→v=−1.5um=-\frac{v}{u}\to v=-1.5um=−uv→v=−1.5u
1/v+1/u=2/R→−1/(1.5u)+1/u=2/R→1/v+1/u=2/R\to -1/(1.5u)+1/u=2/R\to1/v+1/u=2/R→−1/(1.5u)+1/u=2/R→
u=0.5R/3=0.5⋅40.5/3=6.75 (cm)u=0.5R/3=0.5\cdot40.5/3=6.75\ (cm)u=0.5R/3=0.5⋅40.5/3=6.75 (cm) . Answer
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