Question

An 8 kg bowling ball is at rest and a 5 kg bowling ball rolls towards it. Upon collision, the heavier ball moves with a velocity of 3 m/s and a lighter ball stops moving. What is the velocity of the lighter ball before collision?

Answer 1

$mv=MV\to v=MV/m=8\cdot3/5=4.8\ (m/s)$ . Answer