Answer to Question #264701 in Physics for Kie

Question #264701

An 8 kg bowling ball is at rest and a 5 kg bowling ball rolls towards it. Upon collision, the heavier ball moves with a velocity of 3 m/s and a lighter ball stops moving. What is the velocity of the lighter ball before collision?

Expert's answer

"mv=MV\\to v=MV\/m=8\\cdot3\/5=4.8\\ (m\/s)" . Answer

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