Question

A box is sitting on a ramp

angled at 20°. If the box weighs

50 N, what is the normal force

on the box?

Answer 1

The weight is $P = 10N$, angle $\alpha =20\degree$, normal force is $N$ and friction force is $F_{fr}$. Using the second Newton's law in a projection on y-axis, obtain:

$$N = P\cos\alpha\\ N = 50N\cdot \cos20\degree \approx 47N$$

Answer. 47N.