Answer to Question #264378 in Physics for boss

Question #264378

Boat A moves with constant velocity of 6m/s. starting from position down. Fine the angle in order for the projectile to hit the boat 5 seconds after starting, under the conditions given. How high is the hill above the water?


1
Expert's answer
2021-11-11T17:08:27-0500

"vt+90=30\\cdot\\cos\\alpha\\cdot t\\to \\cos\\alpha=\\frac{vt+90}{30t}=\\frac{6\\cdot5+90}{30\\cdot5}=0.8\\to"


"\\alpha=36.87\u00b0" . Answer


"t_1=\\frac{30\\cdot\\sin36.87\u00b0}{9.8}=1.84\\ (s)"


The time of movement of the projectile in the vertical direction


"t_2=5-1.84=3.16\\ (s)"


"h=gt^2\/2=9.8\\cdot3.16^2\/2\\approx49\\ (m)"


"h_1=(30\\cdot\\sin36.87\u00b0)^2\/(2\\cdot9.8)=16.53\\ (m)"


"y=49-16.53=32.47\\ (m)" . Answer







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