Question

How many pounds of force would it take for a class three lever to develop 230

pounds of resultant force if applied force arm is 18 and ¼ inches, and the resultant

force arm is 36 and 7/8 inches?

Answer 1

The force is

$$F=f\frac{L}{l}=230\frac{36+7/8}{18+1/4}=465\text{ lbf}$$