A particle is oscillating with simple harmonic motion of amplitude 15cm and frequency 4 Hz.
Compute (i) the maximum values of acceleration and velocity, (ii) the acceleration and velocity when
the displacement is 9cm.
(i) vmax=0.15⋅2π⋅4=3.8 m/s.amax=0.15⋅(2π⋅4)2=95 m/s2.v_\text{max}=0.15·2\pi·4=3.8\text{ m/s}.\\ a_\text{max}=0.15·(2\pi·4)^2=95\text{ m/s}^2.vmax=0.15⋅2π⋅4=3.8 m/s.amax=0.15⋅(2π⋅4)2=95 m/s2.
(ii) v=0.09⋅2π⋅4=2.3 m/s.a=0.09⋅(2π⋅4)2=57 m/s2.v=0.09·2\pi·4=2.3\text{ m/s}.\\ a=0.09·(2\pi·4)^2=57\text{ m/s}^2.v=0.09⋅2π⋅4=2.3 m/s.a=0.09⋅(2π⋅4)2=57 m/s2.
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