Unpolarized light with an intensity of 120 W falls on a polarizer and analyser. The angle between the transmission axes of the polarizer and analyser is 72°. What is the intensity of the light leaving the analyser, reaching the photocell?
Question 3 options:
A)
No option is correct
B)
11 W
C)
5.7 W
D)
60 W
E)
19 W
"I=\\frac{1}{2}I_0\\cos^2\\alpha=\\frac{1}{2}\\cdot120\\cdot\\cos^272\u00b0=5.7\\ (W)"
C) 5.7 W . Answer
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