Question #263232

4. A rope of negligible mass is stretched horizontally between two supports that are 3.44 m apart. When an

object of weight 3160 N hung at the center of the rope, the rope is observed to sag by 35.0 cm. What is

the tension in the rope?


Expert's answer

The tension is


T=LF4s=3.44316040.35=7765 N.T=\frac{LF}{4s}=\frac{3.44·3160}{4·0.35}=7765\text{ N}.


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