Question #263211

An astronaut drops a feather from 1.2m above the surface of the moon. If the acceleration of gravity on the moon is 1.62m/s2 downward how long does it take the feather to hit the moon’s surface?


1
Expert's answer
2021-11-09T13:26:21-0500

The time is


t=2h/g=1.22 s.t=\sqrt{2h/g}=1.22\text{ s}.


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