Answer to Question #263139 in Physics for King and Queen

Question

A piece of stone is attached to one end of spring is whirled round in a horizontal circle of radius 7m when the constant speed of the stone is 40ms-1 calculate the centripetal acceleration

Answer 1

Given:

$r=7\:\rm m$

$v=40\:\rm m/s$

The centripetal acceleration is given by

$$a=\frac{v^2}{r}=\frac{40^2}{7}=229\:\rm m/s^2$$