Question #263136

A piece of stone attached to one end of spring is whirled round in a horizontal circle of radius 7m .when the constant speed of the stone is 40ms-1 calculate the centripetal acceleration


1
Expert's answer
2021-11-09T10:58:56-0500

The centripetal acceleration is


ac=v2/r=229 m/s2.a_c=v^2/r=229\text{ m/s}^2.


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