Answer to Question #263135 in Physics for Solomon Ossai

Question #263135

A ball is thrown vertically upward from ground level hits the ground after 4s.calculate the maximum height it reached during it's journey

Expert's answer

The maximum height is

"H=\\frac{g(T\/2)^2}{2}=\\frac{gT^2}{8}=\\frac{9.8\u00b74^2}{8}=19.6\\text{ m}."

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