Answer to Question #263135 in Physics for Solomon Ossai

Question

A ball is thrown vertically upward from ground level hits the ground after 4s.calculate the maximum height it reached during it's journey

Answer 1

The maximum height is

$$H=\frac{g(T/2)^2}{2}=\frac{gT^2}{8}=\frac{9.8·4^2}{8}=19.6\text{ m}.$$