Fnet=ma→F−mg=ma→a=F−mgm=1040−100⋅9.81100≈0.6 (m/s2)F_{net}=ma\to F-mg=ma\to a=\frac{F-mg}{m}=\frac{1040-100\cdot9.81}{100}\approx0.6 \ (m/s^2)Fnet=ma→F−mg=ma→a=mF−mg=1001040−100⋅9.81≈0.6 (m/s2) . Answer
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