Question #262414

Emmanuel Zacchini launched as a human cannonball in 1940 soared over three Ferris wheels each 18.0 m high covering a horizontal distance of 10.63m. a.) Assuming that the point of projection is 2.50 m above the ground and that he landed safely on a net placed at the same level, find his initial velocity. b.) Assuming that he missed the net and landed on the ground, with what velocity will he strike the ground?


Expert's answer

a) We have range and max. height:


R=v2sin(2θ)g=v22sinθcosθg, y=v2sin2θ2g=v2sinθsinθ2g, yR=14tanθ, θ=arctan4yR=arctan4(182.5)10.63=80°. v=Rgsin(2θ)=17.5 m/s.R=\frac{v^2\sin(2\theta)}{g}=\frac{v^2·2\sin\theta·\cos\theta}{g},\\\space\\ y=\frac{v^2\sin^2\theta}{2g}=\frac{v^2·\sin\theta·\sin\theta}{2g},\\\space\\ \frac yR=\frac14\tan\theta,\\\space\\ \theta=\arctan\frac{4y}{R}=\arctan\frac{4(18-2.5)}{10.63}=80°.\\\space\\ v=\sqrt\frac{Rg}{\sin(2\theta)}=17.5\text{ m/s}.

b) He fell from the max. height of (18) m to the ground:



uy=2gH=18.8 m/s,ux=vx=vcosθ=3.04 m/s,u=ux2+uy2=19 m/s.u_y=\sqrt{2gH}=18.8\text{ m/s},\\ u_x=v_x=v\cos\theta=3.04\text{ m/s},\\ u=\sqrt{u_x^2+u_y^2}=19\text{ m/s}.


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