Question #261598

A carousel is initially at rest, Ron is seating 3.0 m from the center. At an initial t=0, the carousel is given a constant angular acceleration of a=0.065 rad /s². At t=10.0 s, find the following quantities: (a) angular velocity of the carousel, (b) linear velocity of Ron, (c) his tangential acceleration, (d) his centripetal acceleration, and (e) his total acceleration.






Expert's answer

(a) The angular velocity of the carousel can be found as follows:


ω=ω0+αt=0+0.065 rads2×10 s=0.65 rads.\omega=\omega_0+\alpha t=0+0.065\ \dfrac{rad}{s^2}\times10\ s=0.65\ \dfrac{rad}{s}.

(b) Linear velocity of Ron can be found as follows:


v=ωr=0.65 rads×3.0 m=1.95 ms.v=\omega r=0.65\ \dfrac{rad}{s}\times3.0\ m=1.95\ \dfrac{m}{s}.

(c) Tangential acceleration of Ron can be found as follows:


at=αr=0.065 rads2×3.0 m=0.195 ms2.a_t=\alpha r=0.065\ \dfrac{rad}{s^2}\times3.0\ m=0.195\ \dfrac{m}{s^2}.

(d) Centripetal acceleration of Ron can be found as follows:


ac=v2r=(1.95 ms)23.0=1.27 ms2.a_c=\dfrac{v^2}{r}=\dfrac{(1.95\ \dfrac{m}{s})^2}{3.0}=1.27\ \dfrac{m}{s^2}.

(e) Total acceleration of Ron can be found as follows:


a=at2+ac2=(0.195 ms2)2+(1.27 ms2)2=1.28 ms2.a=\sqrt{a_t^2+a_c^2}=\sqrt{(0.195\ \dfrac{m}{s^2})^2+(1.27\ \dfrac{m}{s^2})^2}=1.28\ \dfrac{m}{s^2}.
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