Answer to Question #261574 in Physics for Crage

Question

Transform equation T=2pi√(L-h)/g into linear form as h=

Answer 1

Expressing $h$, find:

$$\dfrac{L-h}{g} = \dfrac{T^2}{4\pi^2}\\ L-h = \dfrac{gT^2}{4\pi^2}\\ h = L - \dfrac{gT^2}{4\pi^2}$$

Answer. $h = L - \dfrac{gT^2}{4\pi^2}$