Answer to Question #260942 in Physics for jae

Question

A 1,348 kg truck moving at 12 m/s runs into a concrete wall. It takes 0.5 second for the truck to

completely stop. What is the magnitude of force exerted on the truck during the collision?

Answer 1

The force is

$$F=\Delta I/t=m\Delta v/t=1348(12-0)/0.5=\\ =80880\text{ N}.$$