A simple pendulum with a frequency of 0.056 Hz is as long as the largest known specimen of Pacific giant seaweed. What is this length?
T=2πl/g→l=gT2/(4π2)=9.81⋅0.0562/(4⋅3.142)=T=2\pi\sqrt{l/g}\to l=gT^2/(4\pi^2)=9.81\cdot0.056^2/(4\cdot3.14^2)=T=2πl/g→l=gT2/(4π2)=9.81⋅0.0562/(4⋅3.142)=
=0.00078 (m)=0.78 (mm)=0.00078\ (m)=0.78\ (mm)=0.00078 (m)=0.78 (mm)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments