compute algebraicially the resultant of the following coplanar forces: 100 N at 30 degrees, 141.4N at 45 degrees and 100N at 240 degrees
x=100⋅cos30°+141.4⋅cos45°+100⋅cos240°=x=100\cdot\cos30°+141.4\cdot\cos45°+100\cdot\cos240°=x=100⋅cos30°+141.4⋅cos45°+100⋅cos240°=
=136.59 (N)=136.59\ (N)=136.59 (N)
y=100⋅sin30°+141.4⋅sin45°+100⋅sin240°=y=100\cdot\sin30°+141.4\cdot\sin45°+100\cdot\sin240°=y=100⋅sin30°+141.4⋅sin45°+100⋅sin240°=
=63.4 (N)=63.4\ (N)=63.4 (N)
Ftotal=136.592+63.42=150.6 (N)F_{total}=\sqrt{136.59^2+63.4^2}=150.6\ (N)Ftotal=136.592+63.42=150.6 (N)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment