Question #260773

compute algebraicially the resultant of the following coplanar forces: 100 N at 30 degrees, 141.4N at 45 degrees and 100N at 240 degrees



Expert's answer

x=100⋅cos⁡30°+141.4⋅cos⁡45°+100⋅cos⁡240°=x=100\cdot\cos30°+141.4\cdot\cos45°+100\cdot\cos240°=


=136.59 (N)=136.59\ (N)


y=100⋅sin⁡30°+141.4⋅sin⁡45°+100⋅sin⁡240°=y=100\cdot\sin30°+141.4\cdot\sin45°+100\cdot\sin240°=


=63.4 (N)=63.4\ (N)


Ftotal=136.592+63.42=150.6 (N)F_{total}=\sqrt{136.59^2+63.4^2}=150.6\ (N)




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