Question #260659

A boy of mass 50g runs a step of 5m each in 2mins.find the work done by the boy

1
Expert's answer
2021-11-04T10:17:17-0400

Let m=50g=0.05kgm=50g = 0.05kg. The work done against gravity is then:


W=mghW = mgh

where h=5mh = 5m is the height, g=9.8m/s2g = 9.8m/s^2 is the gravitational acceleration. Thus, obtain:


W=0.05kg9.8m/s25m=2.45JW = 0.05kg\cdot 9.8m/s^2\cdot5m = 2.45J

ANswer. 2.45 J.


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