A boy of mass 50g runs a step of 5m each in 2mins.find the work done by the boy
Let m=50g=0.05kgm=50g = 0.05kgm=50g=0.05kg. The work done against gravity is then:
where h=5mh = 5mh=5m is the height, g=9.8m/s2g = 9.8m/s^2g=9.8m/s2 is the gravitational acceleration. Thus, obtain:
ANswer. 2.45 J.
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