Answer to Question #260068 in Physics for haze

Question

To pull a crate a distance of 2 m across the floor, a rope is used to apply an horizontal force of 180 N. A frictional force of 70 N opposes this motion. What is the total work done on the crate in J? (Hint: Calculate the work done by the rope and by the friction first.)

Answer 1

The total work:

$$W=F_\text{net}d=(180-70)2=220\text{ J}.$$