Answer to Question #260008 in Physics for Mule

Question

The alternator on a truck engine produces 350Wof electric power when it rotates at 4000 rev/min. If it is 95 percent efficient, what should the difference (in newtons) between the tensions in the tight and slack parts of its V-belt drive be? The diameter of the alternator’s pulley is 10 cm.  

Answer 1

$$\tau=\frac P\omega,\\\space\\ T=\frac \tau r=\frac{P}{\omega r},\\\space\\ \Delta T=T(1-\eta)=\frac{P}{\omega r}(1-\eta)=5.25\text{ N}.$$