Answer to Question #259568 in Physics for nxx

Question

suppose that two objects attract each other with a gravitational force of 16 units. if the distance between the two objects is reduced by a factor of 5, then what is the new force of attraction between the two objects?

Answer 1

$$F_{new}=\dfrac{Gm_1m_2}{(\dfrac{d}{5})^2}=\dfrac{Gm_1m_2}{\dfrac{1}{25}d^2}=25\dfrac{Gm_1m_2}{d^2}=25F,$$ $$F_{new}=25\times16\ units=400\ units.$$