Question #257966

A sample of pitchblende contains 50 kg uranium. The half-life of uranium is 4.5×10⁹ yr. The atomic weight of uranium is 238.4. The total number of uranium atoms in the beginning is 1.269×10²⁶ atoms. Calculate the age of the sample

Expert's answer

Let's first find the number of atoms in a sample of pitchblende:


N=mNAMm,N=\dfrac{mN_A}{M_m},N=50 kg×6.022×1023 mol−1238.4×10−3 kgmol=1.263×1026 atoms.N=\dfrac{50\ kg\times6.022\times10^{23}\ mol^{-1}}{238.4\times10^{-3}\ \dfrac{kg}{mol}}=1.263\times10^{26}\ atoms.

Let's use the formula for radioactive decay:


N=N0e−λt,N=N_0e^{-\lambda t},NN0=e−λt,\dfrac{N}{N_0}=e^{-\lambda t},ln(NN0)=ln(e−0.693T1/2t),ln(\dfrac{N}{N_0})=ln(e^{-\dfrac{0.693}{T_{1/2}}t}),ln(NN0)=−0.693T1/2t,ln(\dfrac{N}{N_0})=-\dfrac{0.693}{T_{1/2}}t,t=(ln(NN0)−0.693)T1/2,t=(\dfrac{ln(\dfrac{N}{N_0})}{-0.693})T_{1/2},t=(ln(1.263×1026 atoms1.263×1026 atoms)−0.693)×4.5×109 yr=3.1×107 yr.t=(\dfrac{ln(\dfrac{1.263\times10^{26}\ atoms}{1.263\times10^{26}\ atoms})}{-0.693})\times4.5\times10^9\ yr=3.1\times10^7\ yr.
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