Calculate the cut-off wavelength for aluminium, which has a work function of 4.08 eV. Will photoelectrons be emitted when radiation of wavelength 400 nm is incident on an aluminium surface?
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Expert's answer
2021-10-31T18:12:17-0400
Determine the cut-off wavelength:
"\\lambda_c=\\frac{hc}{W}=304\\text{ nm}."
400 nm is greater than the cut-off wavelength, therefore, the photons have less energy and the photoelectrons will not be emitted.
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