Answer to Question #257140 in Physics for Banjjycruise

Question #257140
  • When a box of mass 45kg is given as the initial speed pf 5m/s, it slides along a horizontal floor distance of 3m before coming to rest. What is the coefficient of dynamic friction between the box and the floor.
1
Expert's answer
2021-10-27T10:16:58-0400

Ff=maμmg=m(v2/2s)μ=v2/(2sg)=52/(239.8)=0.43F_f=ma\to \mu mg=m(v^2/2s)\to\mu=v^2/(2sg)=5^2/(2\cdot3\cdot9.8)=0.43


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment