Question #257036

There are two cars.First one have V=7.8 m/s.Second one have V=5 m/s.They have same direction but slower one has starter point 38 meters ahead of faster one.Questions:when fast cars will overtake slower?What is the length of the journey they have individually traversed?


1
Expert's answer
2021-10-26T17:18:21-0400
7.8t=5t+38t=13.6 sS=7.8(13.6)=106 ms=10638=68 m7.8t=5t+38\\t=13.6\ s\\S=7.8(13.6)=106\ m\\s=106-38=68\ m


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