Question #256969

1. When a cylindrical capacitor is given a charge of 0.500 nC, a potential difference of

20.0 V is measured between the cylinders.

a.

What is the capacitance of this system?


1
Expert's answer
2021-10-26T17:18:37-0400
C=qUC=0.510920=2.51011 FC=\frac{q}{U}\\C=\frac{0.5\cdot10^{-9}}{20}=2.5\cdot10^{-11}\ F


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