Question #256392

 A constant force ๐‘ฎโƒ— โƒ—

= (๐Ÿ“. ๐Ÿ๐Ÿ๐’‹ฬ‚ + ๐Ÿ”. ๐Ÿ๐Ÿ ๐’Œ ฬ‚)๐‘ต is applied to a particle that

undergoes a displacement ๐“ตโƒ— โƒ— โƒ—

= (๐Ÿ’. ๐Ÿ๐Ÿ๐’‹ฬ‚  โˆ’ ๐Ÿ•. ๐Ÿ๐Ÿ ๐’Œ ฬ‚)๐’. (a) the work done by 

the force, and (b) the component of the force in the direction of the 

displacement.


1
Expert's answer
2021-10-26T09:42:00-0400

(a) The work is


W=Gโƒ—โ‹…lโƒ—=5.11โ‹…4.11+6.11โ‹…(โˆ’7.11)=27.1 J.W=\vec Gยท\vec l=5.11ยท4.11+6.11ยท(-7.11)= 27.1\text { J}.

(b) The component of the force is


Gl=W/โˆฃlโˆฃ=27.1/4.112+7.112=3.30 N.G_l=W/|l|=27.1/\sqrt{4.11^2+7.11^2}=3.30\text{ N}.


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