Question

2. To go to a nearby convenience store from her dormitory, a student walks 12.0 m, north and 5.0 m, east. What is the student’s displacement from her dormitory? (NB. Displacement is a vector quantity hence you need to determine its specific direction)

Answer 1

The magnitude is

$$d=\sqrt{12^2+5^2}=13\text{ m},\\\space\\ \theta=\arctan\frac{12}{5}=67°\text{ N of E}.$$