Question #255516

A 530.4 N box is resting on a plane inclined at 42.0 degrees to the horizontal. Find the parallel force (force parallel to the plane) acting on the box.


1
Expert's answer
2021-10-24T18:26:47-0400
F=Wsinθ=530.4 N×sin42=355 N.F_{||}=Wsin\theta=530.4\ N\times sin42^{\circ}=355\ N.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS