Answer to Question #255096 in Physics for Enqu G

Question #255096

A stone throws horizontally with a certain initial velocity from a top of building. If the stone takes 3 sec to hit the ground 60m from the bottom of the building then find

1-initial velocity of the stone

2-the hight if the building

3-the horizontal and the vertical components of the velocity


1
Expert's answer
2021-10-24T18:25:22-0400

The initial velocity:


v=R/t=60/3=20 m/s.v=R/t=60/3=20\text{ m/s}.

The height:


h=gt2/2=44.1 m.h=gt^2/2=44.1\text{ m}.

The horizontal component is the same, while the vertical component is


vy=2gh=29.4 m/s.v_y=\sqrt{2gh}=29.4\text{ m/s}.


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