Question

A 12 Kg box is put on the surface of an inclined plane at 38 ° with the horizontal. The coefficient of kinetic friction is 0.35. Determine the magnitude of the force exerted by the inclined plane on the box.

Answer 1

Given:

$m=12\:\rm kg$

$\theta=38^{\circ}$

$\mu=0.35$

The friction force

$$F=\mu N=\mu mg\cos\theta$$

$$F=0.35*12*9.8*\cos38^{\circ}=32.4\:\rm N$$