Question #254588

A fidget spinner of radius 0.05 m has a moment of inertia kg m2

and


is rotating at 8.4 rad s-1


. A large fly whose mass is 0.3 kg lands onto the edge of

the rotating spinner. Calculate the angular speed of the system after the fly falling

onto the spinner.


Expert's answer

Given:

r=0.05mr=0.05\:\rm m

I0=1.25104kgm2I_0=1.25*10^{-4}\:\rm kg\cdot m^2

ω1=8.4rad/s\omega_1=8.4\:\rm rad/s

m=0.3kgm=0.3\:\rm kg


The law of conservation of angular momentum

I0ω1=(I0+mr2)ω2I_0\omega_1=(I_0+mr^2)\omega_2

Hence


ω2=I0ω1/(I0+mr2)=1.251048.4/(1.25104+0.30.052)=1.2rad/s\omega_2=I_0\omega_1/(I_0+mr^2)\\ =1.25*10^{-4}*8.4/(1.25*10^{-4}+0.3*0.05^2)\\ =1.2\:\rm rad/s


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS