Question #254588

A fidget spinner of radius 0.05 m has a moment of inertia kg m2

and


is rotating at 8.4 rad s-1


. A large fly whose mass is 0.3 kg lands onto the edge of

the rotating spinner. Calculate the angular speed of the system after the fly falling

onto the spinner.


1
Expert's answer
2021-10-21T16:33:46-0400

Given:

r=0.05mr=0.05\:\rm m

I0=1.25104kgm2I_0=1.25*10^{-4}\:\rm kg\cdot m^2

ω1=8.4rad/s\omega_1=8.4\:\rm rad/s

m=0.3kgm=0.3\:\rm kg


The law of conservation of angular momentum

I0ω1=(I0+mr2)ω2I_0\omega_1=(I_0+mr^2)\omega_2

Hence


ω2=I0ω1/(I0+mr2)=1.251048.4/(1.25104+0.30.052)=1.2rad/s\omega_2=I_0\omega_1/(I_0+mr^2)\\ =1.25*10^{-4}*8.4/(1.25*10^{-4}+0.3*0.05^2)\\ =1.2\:\rm rad/s


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