Answer to Question #253949 in Physics for Kristine

Question #253949

A ball is thrown upward with an initial velocity of 15 m/s at an angle of 60.0° above the horizontal. Use energy conservation to find the ball’s greatest height above the ground.

Expert's answer

"mv^2_y\/2=mgh\\to h=v^2\\sin^2\\alpha\/(2g)" . Answer

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